Answer:option Bx = 1 + 3√6 or x = 1 - 3√6 Step-by-step explanation:Given in the question an equation,3(x-1)² - 162 = 0rearrange the x terms to the left and constant to the right3(x-1)² = 162(x-1)² = 162/3(x-1)² = 54 Take square root on both sides√(x-1)² = √54 x - 1 = ±3√6x = ±3√6 + 1So we have two values for xx = 3√6 + 1 OR x = -3√6 + 1