Which situation could NOT represent a proportional relationship? A) The cost of purchasing candy bars at a price of $1.25 per candy bar. B) The number of cookies produced in a factory at a rate of 1,000 cookies per hour. C) The cost of transporting an automobile for a charge of $1.00 per mile with a pick-up fee of $100. D) The cost of a field trip to a museum for a group of high school students at a cost of $10.00 per student.

Answer:Option C. The cost of transporting an automobile for a charge of $1.00 per mile with a pick-up fee of $100Step-by-step explanation:we know that           A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form [tex]y/x=k[/tex] or [tex]y=kx[/tex] In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin verify each casecase A) The cost of purchasing candy bars at a price of $1.25 per candy bar.       Lety------> the costx----> the number of candy barsThe linear equation that represent the situation is y=1.25x -------> represent a proportional relationshipcase B) The number of cookies produced in a factory at a rate of 1,000 cookies per hourLety------> the number of cookiesx----> the number of hoursThe linear equation that represent the situation is y=1,000x -------> represent a proportional relationshipcase C) The cost of transporting an automobile for a charge of $1.00 per mile with a pick-up fee of $100Lety------> the costx----> the number of milesThe linear equation that represent the situation is y=x+100 -------> not represent a proportional relationshipcase D) The cost of a field trip to a museum for a group of high school students at a cost of $10.00 per studentLety------> the costx----> the number of studentsThe linear equation that represent the situation is y=10x -------> represent a proportional relationship