Find the equation of a line parallel to y - 5x = 10 that passes through the point (3, 10). (answer in slope-intercept form)

y = 5x - 5 is the equation of a line parallel to y - 5x = 10 that passes through the point (3, 10) in slope intercept formSolution:Given that line parallel to y - 5x = 10 that passes through the point (3, 10)To find: equation of line in slope intercept formThe slope intercept form is given as:y = mx + cWhere "m" is the slope of line and "c" is the y - interceptLet us first find slope of liney - 5x = 10y = 5x + 10On comparing y = 5x + 10 with slope intercept form, we get m = 5Thus slope of given line is 5We know that slopes of parallel lines are equalSo the slope of line parallel to given line is also 5Now we have to find the equation of line with slope m = 5 and passes through point (3, 10)Substitute m = 5 and (x, y) = (3, 10) in slope intercept form,10 = 5(3) + c10 = 15 + cc = - 5Thus the required equation is:Substitute c = -5 and m = 5 in eqn 1y = 5x - 5Thus the required equation of line is found